sir

To accurately answer your question we need to be clear about the binary value of the addresses. This will show us whether there is a wildcard mask that will match them. So the binary values of the last octet are:

156 is 10011100

158 is 10011110

160 is 10100000

162 is 10100010

As Edwin says one way to solve this is to create 4 host specific entries in your access list. There is also a possibility to use wildcard mask if you create 2 permit statements. You could:

permit 134.144.152.156 0.0.0.2 (which covers 156 and 158) and

permit 134.144.152.160 0.0.0.2 (which covers 160 and 162) and

HTH

Rick