Help: IPv6 Route Summarization

Answered Question
Jul 19th, 2007
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Hi Guys,


Can someone explain to me how to summarize an IPv6 network. Because with the book I am reading, I can't understand how the author came up with this.


IPv6 Networks:

2001:DB8:0:10::/64

2001:DB8:0:11::/64

2001:DB8:0:12::/64

2001:DB8:0:13::/64


IPv6 Summary:

2001:DB8:0:10::/62


Does it still have to deal with bits for summarization?


Thanks,

John

Correct Answer by Edison Ortiz about 10 years 1 week ago

Let's break it down:


0x10 = 0000000000010000

0x11 = 0000000000010001

0x12 = 0000000000010010

0x13 = 0000000000010011


The common bits are the first 14 bits, correct ?


Every colon you have 16 bits and the summarized portion is located in after the third colon, correct ?


So you have 16 x 3 = 48


Then you add 14 bits from the fourth column (the common bits we discussed above) and you have 62.


HTH,



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Correct Answer
Edison Ortiz Fri, 07/20/2007 - 05:44
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Let's break it down:


0x10 = 0000000000010000

0x11 = 0000000000010001

0x12 = 0000000000010010

0x13 = 0000000000010011


The common bits are the first 14 bits, correct ?


Every colon you have 16 bits and the summarized portion is located in after the third colon, correct ?


So you have 16 x 3 = 48


Then you add 14 bits from the fourth column (the common bits we discussed above) and you have 62.


HTH,



John Patrick Lopez Sat, 07/21/2007 - 17:18
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Thank you very much Edison. This solved my problem. I forgot that this is hexadecimal and not decimal. I'm still trying to absorb all the IPv6 fundamentals right now. Thank you so much.=)

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