07-19-2007 07:59 PM - edited 03-03-2019 05:57 PM
Hi Guys,
Can someone explain to me how to summarize an IPv6 network. Because with the book I am reading, I can't understand how the author came up with this.
IPv6 Networks:
2001:DB8:0:10::/64
2001:DB8:0:11::/64
2001:DB8:0:12::/64
2001:DB8:0:13::/64
IPv6 Summary:
2001:DB8:0:10::/62
Does it still have to deal with bits for summarization?
Thanks,
John
Solved! Go to Solution.
07-20-2007 05:44 AM
Let's break it down:
0x10 = 0000000000010000
0x11 = 0000000000010001
0x12 = 0000000000010010
0x13 = 0000000000010011
The common bits are the first 14 bits, correct ?
Every colon you have 16 bits and the summarized portion is located in after the third colon, correct ?
So you have 16 x 3 = 48
Then you add 14 bits from the fourth column (the common bits we discussed above) and you have 62.
HTH,
07-20-2007 05:44 AM
Let's break it down:
0x10 = 0000000000010000
0x11 = 0000000000010001
0x12 = 0000000000010010
0x13 = 0000000000010011
The common bits are the first 14 bits, correct ?
Every colon you have 16 bits and the summarized portion is located in after the third colon, correct ?
So you have 16 x 3 = 48
Then you add 14 bits from the fourth column (the common bits we discussed above) and you have 62.
HTH,
07-21-2007 05:18 PM
Thank you very much Edison. This solved my problem. I forgot that this is hexadecimal and not decimal. I'm still trying to absorb all the IPv6 fundamentals right now. Thank you so much.=)
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