# Help: IPv6 Route Summarization

Jul 19th, 2007

Hi Guys,

Can someone explain to me how to summarize an IPv6 network. Because with the book I am reading, I can't understand how the author came up with this.

IPv6 Networks:

2001:DB8:0:10::/64

2001:DB8:0:11::/64

2001:DB8:0:12::/64

2001:DB8:0:13::/64

IPv6 Summary:

2001:DB8:0:10::/62

Does it still have to deal with bits for summarization?

Thanks,

John

Correct Answer by Edison Ortiz about 9 years 6 months ago

Let's break it down:

0x10 = 0000000000010000

0x11 = 0000000000010001

0x12 = 0000000000010010

0x13 = 0000000000010011

The common bits are the first 14 bits, correct ?

Every colon you have 16 bits and the summarized portion is located in after the third colon, correct ?

So you have 16 x 3 = 48

Then you add 14 bits from the fourth column (the common bits we discussed above) and you have 62.

HTH,

Overall Rating: 5 (2 ratings)

## Replies

Edison Ortiz Fri, 07/20/2007 - 05:44

Let's break it down:

0x10 = 0000000000010000

0x11 = 0000000000010001

0x12 = 0000000000010010

0x13 = 0000000000010011

The common bits are the first 14 bits, correct ?

Every colon you have 16 bits and the summarized portion is located in after the third colon, correct ?

So you have 16 x 3 = 48

Then you add 14 bits from the fourth column (the common bits we discussed above) and you have 62.

HTH,

John Patrick Lopez Sat, 07/21/2007 - 17:18

Thank you very much Edison. This solved my problem. I forgot that this is hexadecimal and not decimal. I'm still trying to absorb all the IPv6 fundamentals right now. Thank you so much.=)