08-03-2007 11:43 AM - edited 03-05-2019 05:42 PM
Hi All,
Could anyone be kind to help with the first six subnets of the following address 172.23.0.0/27 WITHOUT inclusion of subnet zero and please explain to help my understanding.
Regards
Newnetman
08-03-2007 12:03 PM
27 bits are on
11111111.11111111.11111111.11100000
5 bits are variable
2^5 = 32
You need a subnet ID and a broadcast address on each subnet, so starting with the first subnet.
172.23.0.0 [subnet ID]
172.23.0.1-30 [IP for Host]
172.23.0.31 [broadcast for that subnet]
172.23.0.32 [subnet ID]
172.23.0.33-62 [IP for Host]
172.23.0.63 [broadcast for that subnet]
172.23.0.64 [subnet ID]
172.23.0.65-94 [IP for Host]
172.23.0.95 [broadcast for that subnet]
And I will let you do the last 3. The logic is adding 32 to the subnet ID and broadcast address, whatever you have in between those 2 values, they are your IPs for the hosts.
HTH,
08-03-2007 12:06 PM
Your explantion is better :)
08-03-2007 12:23 PM
Both equal in value to the community :)
08-03-2007 12:05 PM
Hi
172.23.0.32
172.23.0.64
172.23.0.96
172.23.0.128
172.23.0.160
172.23.0.192
You can use binary to write this out but a quick way to work it out
/27 = 255.255.255.224
256 - 224 = 32
So you subnets go up in increments of 32.
HTH
Jon
08-03-2007 12:37 PM
Hi,
I think EdisonOrtiz has explained it well, hence rated.
I will just add into that. This document explains it all.
http://www.3com.com/other/pdfs/infra/corpinfo/en_US/501302.pdf
HTH
Shaheen
08-03-2007 12:49 PM
Hi All,
I am most delighted for all your magnificent responses.
I am so proud to call you all my invisible mentors.
May you all be bountifully blessed.
regards
Discover and save your favorite ideas. Come back to expert answers, step-by-step guides, recent topics, and more.
New here? Get started with these tips. How to use Community New member guide