Query about sh version command

Answered Question
Feb 17th, 2008
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Here's the output from one 3640



Router#sh ver

Cisco Internetwork Operating System Software

IOS (tm) 3600 Software (C3640-IS-M), Version 12.2(40), RELEASE SOFTWARE (fc1)

Copyright (c) 1986-2006 by cisco Systems, Inc.

Compiled Thu 12-Oct-06 17:43 by pwade

Image text-base: 0x60008930, data-base: 0x6113C000


ROM: System Bootstrap, Version 11.1(20)AA2, EARLY DEPLOYMENT RELEASE SOFTWARE ()

Router uptime is 2 minutes

System returned to ROM by power-on

System image file is "flash:c3640-is-mz.122-40.bin"


cisco 3640 (R4700) processor (revision 0x00) with 49152K/16384K bytes of memory.Processor board ID 25197303

R4700 CPU at 100Mhz, Implementation 33, Rev 1.0

Bridging software.

X.25 software, Version 3.0.0.

SuperLAT software (copyright 1990 by Meridian Technology Corp).

DRAM configuration is 64 bits wide with parity disabled.

125K bytes of non-volatile configuration memory.

16384K bytes of processor board System flash (Read/Write)


Configuration register is 0x2102





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What's meant by 49152K/16384K bytes of memory ?


Also, what's 125K bytes of non-volatile configuration memory.

16384K bytes of processor board System flash (Read/Write)

Correct Answer by Jon Marshall about 9 years 5 months ago

Hi


The DRAM of 64Mb is shared between Main memory and IOMEM. IOMEM is used for packet processing. So


49152 = Main memory

16384 = IOMEM


No there is no relation as such between the 16384 IOMEM and the 16384 flash.


Jon

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Jon Marshall Sun, 02/17/2008 - 10:25
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Hi


49152K/16384K = 64Mb which is the amount of RAM the router has. RAM is memory used by the router to perform it's tasks.


125K bytes of non-volatile configuration memory - amount of memory used for configuration of router in NVRAM


16384K bytes of processor board System flash - how much flsh memory you havem in this case 16Mb. Flash is used to store the IOS images.


HTH


Jon

zanderzone Sun, 02/17/2008 - 10:34
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Hi Jon! Thanks for the quick answer


I need certain clarification here.


Why doesn't router show 64 mb RAM straightaway, instead of showing it in part i.e 49152K/16384K


Also, is there any relation between 16384K from 49152K/16384K and 16384K board system flash ?

Correct Answer
Jon Marshall Sun, 02/17/2008 - 10:49
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Hi


The DRAM of 64Mb is shared between Main memory and IOMEM. IOMEM is used for packet processing. So


49152 = Main memory

16384 = IOMEM


No there is no relation as such between the 16384 IOMEM and the 16384 flash.


Jon

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