sorry for 1 mistake

R 172.16.0.0 /22 is actually

R 172.16.0.0/16

Can u explain we how u figure that out?

Thanks

Mahesh,

R 172.16.0.0/16 is representing the routing protocol RIP, with the advertise network 172.16.0.0 and subnet musk 255.255.0.0

With more details, where the Host address ranges are 172.16.0.1 - 172.16.255.254. The Subnet ID 172.16.0.0 and the Broadcast 172.16.255.255, where the Max Subnet is 1 only with the host per subnet 64534.

Please rate if I am informative.

Thanks

Goutam

Mahesh

Okay, then the packet 172.16.4.3 would use the 172.16.0.0/16 route. Goutam has explained the range of addressing that 172.16.0.0/16 covers.

Is there anything else you want clarification on ?

Jon

Correct me if i'm wrong but 172.16.4.3 doesn't match any of the routes in the routing table apart from the default route 0.0.0.0/0.

To my knowlege if a packets destination IP does not match a route in the routing table then the packet is disagarded unless a default route is configured. In your case it is 0.0.0.0/0. The default route will be used to forward packets if destination IP does not match a specific route.

Have a look at the second post from the OP. There was a typo in the original post

ie.

172.16.0.0/22

172.16.0.0/22

one of these should have read

172.16.0.0/16

in which case 172.16.4.3 would use this route.

Jon

Yeah i see! thanks for pointing that out!