subnetting.

Unanswered Question
May 7th, 2008
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Hi Friends,


I am pretty difficulty on subnetting.


There is one task from my manager i.e., he gave one IP 10.10.2.30/29 and asked in that how many hosts available and what is the subnetmask.


As my knowledge the subnetmask is 255.255.255.248 am i right.


Can any body help me and how we can define.


Regards,

Nadidu.


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Jon Marshall Wed, 05/07/2008 - 22:57
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Nadidu


Yes /29 = 255.255.255.248


256 - 248 = 8 so your subnets increment by 8.


So


10.10.2.0 255.255.255.248 is first subnet. Then


10.10.2.8/29

10.10.2.16/29



10.10.2.24/29 - this is the subnet you are interested in.


10.10.2.32 is the next subnet address.


Each subnet has to have a broadcast address so


10.10.2.24 = subnet address

10.10.2.31 = broadcast address


10.10.2.25 -> 10.10.2.30 are your useable host addresses.


Jon



cisco_lad2004 Wed, 05/07/2008 - 22:59
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yes , this is the correct mask.

there are different ways to work out numver of hosts.

u could do it this way :


248 ==> (256-248)=8

8 - 2=6( remove 2 for Subnet and Broadcast ) , so you are left with 6 hosts.


subnet 10.10.2.24

Hosts [10.10.2.25-30]

Broadcast 10.10.2.31


HTH


Sam

ilnaiduccna Wed, 05/07/2008 - 23:07
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Hi Sam


Thank you for your good explaination.


What is the 256 (number).


Regards,

naidu.

cisco_lad2004 Thu, 05/08/2008 - 00:40
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Just maths, u can use it to extract what is called "Magic Number" sometimes.


255.255.255.128 ==> 256-128=128

255.255.255.192 ==> 256-192=64

255.255.255.228 ==> 256-228=32


etc..


Pls use rating system.


Sam

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