09-04-2008 01:23 AM - edited 03-03-2019 11:24 PM
Hi all,
Not a difficult question if you know - but i don't so i thought that i'd ask :)
When calculating frame-relay TC what is the formula? I'm getting conflicting information. Is it:
tc = bc/CIR
tc = be/CIR
tc = CIR/bc (or be for that matter)
I know that this is probably more of a Qos issue, but hey, most of us run Qos across a WAN anyway :) Your enlightenment would be greatly appreciated. The reason i ask is that i was just watching some old CBT nuggets and he says that CIR is at the top of the mathematical triangle (with tc x bc underneath), but i wasn't sure of where be fits into this equation.
A colleague says that bc should be at the top of the triangle, but surely Jeremy knows best. Just looking for some clarification.
09-04-2008 01:37 AM
Hello ab,
think of tc like the inverse of a sampling rate it is measured in seconds.
in tc seconds up to BC*8 bits are treated as conforming frames.
CIR is a bit rate so it is expressed in Bits/s
Bc is a byte quantity ( byte so must divide by 8 to get bits)
If Bc is small Tc is small too.
So the first formula should be the right one
tc [sec] = Bc/CIR [bits / bits /sec]
Hope to help
Giuseppe
09-04-2008 01:55 AM
That was a clear and concise answer. Have a 5 from me for your efforts.
Thanks Giuseppe.
Find answers to your questions by entering keywords or phrases in the Search bar above. New here? Use these resources to familiarize yourself with the community: