Trying to load share on two paths to a destination from a router on a serial and fast ethernet interfaces.
both interfaces have minimun bandwidth of 1544Kbp/s and 25100 microsecond of total delay, hence the metric becomes 2300416.
Now i want the serial interface to carry twice as much load as the fast ethernet interface.
To achieve this the author says,
OLD METRIC: 2,300,416 = (6476 + 2510)
NEW METRIC :4,600,832 = 256(6476 + 510 + X).
Following this equation,to find the new delay = 6476 (old min bandwidth + 510 "the sum of the delay without the delay on the serial interface" and this is exactly what i have problem with and will appreciate a thorough explanations of how that is achieved, knowing well that EIGRP uses 50% of interface bandwidth by default, why is that 510 not halve the 1544?.
Thank you all