Re: G.703 Card ...

Unanswered Question
Nov 2nd, 2008

Hi,

[1] I need some advice on the use of the command ' channel-group 0 timeslots 1-31'. I am using a G.703 card.

To my understanding the above command means that there are effectively 32 channels of 64K and can be used for voice or data.

My question is that if I just want to use the total bandwidth of the E1, I should do 'channel-group <channel-group-no> unframed right ? This would effectively give me the total

bandwidth of the link.

[2] With respect of the 'channel-group' command, if I had this for example :-

channel-group 0 timeslots 1

channel-group 8 timeslots 5,7,12-15,20 speed 64

channel-group 12 timeslots 2

What does the numbers of 0, 8 and 12 mean here ? Is it any random number that we can use here ?

Thank you,

Cheers,

- InternetB -

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satish_zanjurne Sun, 11/02/2008 - 22:09

hi,

1. it is not any random number.

2.Based on the channel-group your logical serial interface will be created

e.g if channel-group is 9 serial interface will contain 8

3.For E1 channel-group number range is 0-30

HTH..rate if helpful..

InternetB Sun, 11/02/2008 - 22:55

Hi,

You did not answer my question. My question was :-

My question is that if I just want to use the total bandwidth of the E1, I should do 'channel-group unframed right ? This would effectively give me the total bandwidth of the link.

[2] With respect to the 'channel-group' command, if I had this for example :-

channel-group 0 timeslots 1

channel-group 8 timeslots 5,7,12-15,20 speed 64

channel-group 12 timeslots 2

What does the numbers of 0, 8 and 12 mean here ? Is it any random number that we can use here ? Or rather is there a limit on this number and the timeslots would be 24 channels and 32 channels for T1 and E1 respectively ?

* modified the 2nd question a bit from the earlier posting.

- InternetB -

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