I had some queries running in my mind which iam sure could be cleared in this forum :)
My scenario is like this...
Client-1(b mode)------ AP(auto or mixed mode) ------ Client-2(g mode)
Now suppose Client-1 wants to transfer data to client-2 via AP, what would be the rate of transfer of data
a) 11 Mbps (b mode) - lowest of the two rates
b) 11 Mbps (b mode) from Client-1 to AP and 54Mbps from AP to Client-2 and vice versa.
can someone pl throw some light here.
looing forward for your replies.
It would be at the rate of the lowest throughout link in terms of overall throughput.
Each link will transmit the data at it's native rate. For example, if you had something like this:
The segment between the PC and switch is talking at 10 Meg, the segment between the switch and server is talking at 100 meg. The most you could push from PC --> Server is 10Meg, because that is the "slowest" link. The switch is catching at 10 and throwing at 100.
For data going the other way (100-->10) then the switch must buffer the data arriving at the faster rate until either the 10meg link transmits it, or the data expires in the buffer.
It's not an exact analogy because of the way the wireless protocols schedule the transmission and reception of the traffic (wired switches don't), but the general concept is the same.