ip addressing help please.. Thanks

Unanswered Question
Dec 12th, 2008
User Badges:

192.168.136.15

192.168.136.31

192.168.136.63

192.168.136.127



what is the brodcast address of this interface if the show int fa0/0 shows

internet address

192.168.136.200.23 / 28


can anyone explain pls


Thanks

  • 1
  • 2
  • 3
  • 4
  • 5
Overall Rating: 5 (1 ratings)
Loading.
Giuseppe Larosa Fri, 12/12/2008 - 11:30
User Badges:
  • Super Silver, 17500 points or more
  • Hall of Fame,

    Founding Member

Hello Octorbust


/28 means 4 bits host part a maximum of 14 hosts in the subnet

the broadcast is 1 less the next /28 subnet

the base address is made of all zeros

the addresses in the middle are for the hosts


base address 192.168.136.192

brodcast 192.168.136.207 for 192.168.136.200

usable addresses: 192.168.136.193 -192.168.136.206

base address 192.168.136.16

broadcast 192.168.136.31 for 192.168.136.23

usable addresses: 192.168.136.17-30


Hope to help

Giuseppe



cisco steps Fri, 12/12/2008 - 12:14
User Badges:

Giuseppe



Thanks for the info

now i know that /28 is

x.x.x .1.1.1.1.0.0.0.0

and the number of host is 2^4 - 2 = 14

now how do you come up w/ 192.168.136.207


the only option to chouse from are

192.168.136.15

192.168.136.31

192.168.136.63

192.168.136.127



Richard Burts Fri, 12/12/2008 - 12:18
User Badges:
  • Super Silver, 17500 points or more
  • Hall of Fame,

    Founding Member

  • Cisco Designated VIP,

    2017 LAN, WAN

Giuseppe was confused by your question asking about an address with 5 octets. He condidered the address as 192.168.136.200. Obviously the question really meant to ask about 192.168.136.23.


HTH


Rick

Richard Burts Fri, 12/12/2008 - 12:12
User Badges:
  • Super Silver, 17500 points or more
  • Hall of Fame,

    Founding Member

  • Cisco Designated VIP,

    2017 LAN, WAN

I believe that the question has a mistake in it since the question asks about an address that has 5 octets:

192.168.136.200.23 / 28


Giuseppe gives an answer that is correct if you consider just the first 4 octets. Looking at the context of the question I wonder if the 200 was inserted by error and the question meant to ask about address 192.168.136.23 / 28

in which case the broadcast address would be 192.168.136.31.


HTH


Rick

viyuan700 Mon, 12/29/2008 - 09:08
User Badges:
  • Silver, 250 points or more

Can you post ur problem.

khomitchr Fri, 01/02/2009 - 22:22
User Badges:

Here is a subnet chart you can use that I created for myself. Feel free to use it. I recommend printing it out and you might need to zoom in a little to see the numbers better.


Enjoy

~Roman



Attachment: 
gagamboy15 Sat, 01/03/2009 - 21:07
User Badges:

192.168.136.23 /28


base address = 192.168.136.16

host = 192.168.136.17 to .30

Broadcast = 192.168.136.31


Hope it helps.


Cheers!

Actions

This Discussion