04-09-2009 09:52 AM - edited 03-06-2019 05:06 AM
Hi,
If any could let me know the broadcast address for network
10.0.18.0/16
regards
Neo
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04-09-2009 11:09 AM
Neo
with a /16 ie 255.255 then that is a host address.
ie. 10.0.18.0 255.255.0.0 = 10.0 is the network, everything else is host addresses.
If it was 10.0.18.0/24 then yes that would be a network.
Jon
04-09-2009 09:54 AM
10.0.255.255
04-09-2009 10:36 AM
Hi,
i thought it should be 10.1.17.255
regards
neo
04-09-2009 10:42 AM
Neo
10.0.18.0/16 = 10.0.18.0 255.255.0.0
This means the network is 10.0 and so the broadcast address would indeed be 10.0.255.255.
Jon
04-09-2009 10:56 AM
Hi,
Subnetting is being used over here
and netowrk starts from 10.0.18.0/16.(Its a Class A network with subnetting of Class B). According to me , no of host i should get with subnet mask of 16 = 655356 but if i go with your calculation my no of host would be 60672.
(256 - 18)* 256 = 60928.
please let me know if i am right or wrong
regards
Neo
04-09-2009 11:00 AM
Neo
You do get 65536 ( note not 655356 ).
Not sure why you say my calculation means 256 - 18 ? That's not what i said.
10.0.18.0/16 = network 10.0 which means you have 2 full octets left for hosts
so 256 x 256 = 65536
10.0.18.0 is just a host address in the 10.0.0.0/16 network.
Jon
04-09-2009 11:06 AM
Jon,
This is not a host address , thats a network id 10.0.18.0/16. If you say broad cast address is 10.0.255.255 , then subtracting 18 from 256 ( third octet) multiplied by 256 will give me less than 65536.
Neo
04-09-2009 11:09 AM
Neo
with a /16 ie 255.255 then that is a host address.
ie. 10.0.18.0 255.255.0.0 = 10.0 is the network, everything else is host addresses.
If it was 10.0.18.0/24 then yes that would be a network.
Jon
04-09-2009 11:04 AM
Wrong ;) The hosts per each /16 subnet/network would be 2^16-2 = 65,536-2 = 65,534.
04-09-2009 11:06 AM
Greg
Sorry, yes you are right. I was just trying to emphasize to Neo it shouldn't have been 256 - 18.
Jon
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