Subnet mask problem

Unanswered Question
May 6th, 2009
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hi Folks,

I have this situation where a customer has this addressing.

The customer has subnetted 192.168.1.0 network as follows.

192.168.1.48/28 and 192.168.1.64/28.


the problem is,now they want to match the IP range of 192.168.1.80 to 192.168.1.254 in an access-list. So my problem is, what subnet mask will match the remaining range of 192.168.1.80 to 192.168.1.254 after the initial /28 subnetting ?




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Giuseppe Larosa Wed, 05/06/2009 - 03:55
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Hello Yahaya,

being an ACL you can use multiple lines to be able to cover the required address range.


So the answer is multiple ACL lines:


192.168.1.128 0.0.0.127 matches 192.168.1.128-192.168.1.255


192.168.1.80 0.0.0.15 matches 192.168.1.80-192.168.1.95


192.168.1.96 0.0.0.31 matches 192.168.1.96-192.168.127


you need to see every acl line as made of three using the three blocks.


Hope to help

Giuseppe


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