06-10-2009 05:41 PM - edited 03-04-2019 05:04 AM
Hello All,
Could someone please help me to demystify how an author came about getting answer to the following summarisation as 2000:444:444:4440::/64 ?
2000:444:444:4440::444/64
2000:444:444:4441::444/64
2000:444:444:4442::444/64
2000:444:444:4443::444/64
If the first three WORD (not octet since it's 16bits) will give us 48bit, the fouth WORD, where the summary took place had the first three session on (to me which mean 12 bits) if added to the initial 48bits i believed should be /60, but how come the author had /62 or was it a mistake from him?
Please help,
Kind Regards
06-10-2009 07:25 PM
If you meant the summarized prefix is 2000:444:444:4440::/62 then the author is right.
If you look at the 4th block of 16 bits, it is not the first 12 bits that are identical for the 4 prefixes but rather the first 14 bits, which would lead to a /62 summary.
4440 = 0x0100010001000000
4441 = 0x0100010001000001
4442 = 0x0100010001000010
4443 = 0x0100010001000011
Regards
06-11-2009 04:05 AM
Hritter,
Many thanks for your brilliant explanation that has brought summarsing IPv6 to life for me.
Most grateful for your time.
Regards
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