Hi every body.
I have few questions
Let say i configure the default route using ip route 0.0.0.0 0.0.0.0 188.8.131.52, on a router which is running a routing protocol.
1) will this route be advertised without the redistribution command if router is running:
Thanks a lot.
The ip default-network command applies only to distance vector protocols, i.e. RIP, IGRP and EIGRP. It is not accepted by OSPF or IS-IS. Each protocol may send the default route differently. If you are running RIP, it will send the default route as 0.0.0.0/0. IGRP and EIGRP will just flag that route as a candidate for default route but they will send the route as is, not as 0.0.0.0/0. This creates a requirement that the network must first be included in the (E)IGRP process, only then it can be flagged as a candidate default route.
As to your scenario: if you configure the default network on R2, nothing will actually happend. The R2 will have a candidate default route pointing towards R3 but it will not generate a default route here because the network 10.0.0.0/8 was already discovered by the routing protocol in question. You can not take a route discovered by a particular routing protocol and having it further redistributed by that protocol as a candidate default route. Correctly, if you want to declare some route as a candidate default network using the ip default-network, it must first be present in your routing table from some other source (other routing protocol or a static entry).
You might want to check out the following link
it will not be redistributed by default in any routing protocol. There are specific commands in each routing protocol to enable redistribution of a default route.