Something looks wierd. Does this mean that the IP address of the serial (S0) interface is 172.16.10.64? If this is correct, with a 24-bit subnet mask, then .1-.254 are available (except for .64 since it is already in use)for NATing purposes. The range that they have specified would be valid for the network 172.16.10.0 /26, though then the S0 interface could not have the .64 address.
The range that you have specified (.65-.126) is 172.16.10.64 /26
They are actually both wrong. Can you post the link where you read this?
I looked at the link - they are just defining a pool of available addresses for NAT (not overloading) to be .1 - .63. So, in effect, this example is correct. They could, however use the whole /24 network for NAT if they wanted to, minus the .64 (S0) address.
By the way, just defining a network of 172.16.10.64 does not necessarily mean that it has to be a /26 - this could be variably subnetted to whatever you need. /26 just means that you are using .65-.126 as available addresses, with .127 being your broadcast address. You could alternatively, for example, use 172.16.10.64 /27 or /28, /29, /30
for networks of 172.16.10.65 - 94, 172.16.10.65 - .78, etc.
Hi everyone, I would like to thank you in advance for any help you can provide a newcomer like myself!
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