First of all sorry if this question is very easy. I am a new student in networking, so I am still learning the basics. I have a problem that I have been working on for a while, but can't figure what I am doing wrong. I have been given an address "172.16.128.0/19". I want to divide this address into two equal subnets, but can't figure out how:
This is what I have done:
128 64 32 16| 8 4 2 1
172.16.x x x x | x x x x.0
2 4 8 16
1 0 0 0
I have drawn my line for /19, and assigned 1 to subnet 2 and 0s to those that are not subnet 2. I can't figure out how to find a IP address for first network and second network.
this looks like some sort of exam question to me to be honest. With the /17 mask, you would get exactly two subnets. The /20 mask would leave another 14 unused subnets. I don't know which of the two the OP was looking for...
So many folks have their own way of doing subnetting. Having learned all the ways long and short I highly recommend Lazaro Diaz.
"Satisfaction does not come from knowing the solution, it comes from knowing why." - Rosalind Franklin
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