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Webcast-Catalyst9k
New Member

ip addressing help please.. Thanks

192.168.136.15

192.168.136.31

192.168.136.63

192.168.136.127

what is the brodcast address of this interface if the show int fa0/0 shows

internet address

192.168.136.200.23 / 28

can anyone explain pls

Thanks

9 REPLIES
Hall of Fame Super Silver

Re: ip addressing help please.. Thanks

Hello Octorbust

/28 means 4 bits host part a maximum of 14 hosts in the subnet

the broadcast is 1 less the next /28 subnet

the base address is made of all zeros

the addresses in the middle are for the hosts

base address 192.168.136.192

brodcast 192.168.136.207 for 192.168.136.200

usable addresses: 192.168.136.193 -192.168.136.206

base address 192.168.136.16

broadcast 192.168.136.31 for 192.168.136.23

usable addresses: 192.168.136.17-30

Hope to help

Giuseppe

New Member

Re: ip addressing help please.. Thanks

Giuseppe

Thanks for the info

now i know that /28 is

x.x.x .1.1.1.1.0.0.0.0

and the number of host is 2^4 - 2 = 14

now how do you come up w/ 192.168.136.207

the only option to chouse from are

192.168.136.15

192.168.136.31

192.168.136.63

192.168.136.127

Hall of Fame Super Gold

Re: ip addressing help please.. Thanks

Giuseppe was confused by your question asking about an address with 5 octets. He condidered the address as 192.168.136.200. Obviously the question really meant to ask about 192.168.136.23.

HTH

Rick

Re: ip addressing help please.. Thanks

You can use some online calculators for easy use, just in case:

http://www.tech-faq.com/calculate-broadcast-address.shtml

But to learn more about it, I would suggest you read the Jeoff Doyle Vol 1 or any relevant ciscopress books, may be CCNA !

Hall of Fame Super Gold

Re: ip addressing help please.. Thanks

I believe that the question has a mistake in it since the question asks about an address that has 5 octets:

192.168.136.200.23 / 28

Giuseppe gives an answer that is correct if you consider just the first 4 octets. Looking at the context of the question I wonder if the 200 was inserted by error and the question meant to ask about address 192.168.136.23 / 28

in which case the broadcast address would be 192.168.136.31.

HTH

Rick

New Member

Re: ip addressing help please.. Thanks

I would like to help me with subnetting class b and A.

Silver

Re: ip addressing help please.. Thanks

Can you post ur problem.

New Member

Re: ip addressing help please.. Thanks

Here is a subnet chart you can use that I created for myself. Feel free to use it. I recommend printing it out and you might need to zoom in a little to see the numbers better.

Enjoy

~Roman

New Member

Re: ip addressing help please.. Thanks

192.168.136.23 /28

base address = 192.168.136.16

host = 192.168.136.17 to .30

Broadcast = 192.168.136.31

Hope it helps.

Cheers!

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