I believe that the question has a mistake in it since the question asks about an address that has 5 octets:
192.168.136.200.23 / 28
Giuseppe gives an answer that is correct if you consider just the first 4 octets. Looking at the context of the question I wonder if the 200 was inserted by error and the question meant to ask about address 192.168.136.23 / 28
in which case the broadcast address would be 192.168.136.31.
We are pleased to announce availability of Beta software for 16.6.3. 16.6.3 will be the second rebuild on the 16.6 release train targeted towards Catalyst 9500/9400/9300/3850/3650 switching platforms. We are looking for early feedback from custome...