172.31.128.255/18 is a unicast indeed, please check its subnet mask:
The r3d octet is 1 1 0 0 0 0 0 0 (the first two bits must match, which is 128 meaning that they must be "1 0"
and the 4th octet is 0 0 0 0 0 0 0 0 (which means that the 4th octet can have any values from 0 to 255)
and thus having all ones (255) in the 4th octet is fine to be unicast as the broadcast of this subnet is 172.31.191.255 (all ones in the rest of the bits in the 3rd octets and all ones in the 4th octet).
And accordingly you are right in that the broadcast is 172.31.191.255.
Hi everyone, I would like to thank you in advance for any help you can provide a newcomer like myself!
Im studying the 100-105 book by Odom and am currently on the topic of Port security. I purchased a used 2960 and I'm trying to follow a...
While deploying a number of 18xx/2802/3802 model access points (APs), which run AP-COS as their operating platform. It can be observed on some occasions that while many of their access points were able to join the fabric WLC withou...
I am going to design and build an LAN network under a tunnel underground with long distance between the switches.
I will have 2 Catalyst switches and 8 Industrial IE3000, and they will be connected with fiber.
For now I am planning on use Layer-2 s...