To accurately answer your question we need to be clear about the binary value of the addresses. This will show us whether there is a wildcard mask that will match them. So the binary values of the last octet are:
156 is 10011100
158 is 10011110
160 is 10100000
162 is 10100010
As Edwin says one way to solve this is to create 4 host specific entries in your access list. There is also a possibility to use wildcard mask if you create 2 permit statements. You could:
permit 22.214.171.124 0.0.0.2 (which covers 156 and 158) and
permit 126.96.36.199 0.0.0.2 (which covers 160 and 162) and
Hi everyone, I would like to thank you in advance for any help you can provide a newcomer like myself!
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