Let say we have ipv6 enabled router r1, r1 has two interface so and f 0.
so has ip address 2340:1111:AAAA :2::1/64
fo has ip address 2340: 1111:AAAA:1::/64 eui-64
S0R1 f 0------------------h2
H2 has ip address 2340:1111:AAA:1: 0234: 56FF:FE78:9ABC
r1 receives a ip packet with destination ip address" 2340:1111:AAA:1: 0234: 56FF:FE78:9ABC" . r1 has no entry in arp cache for h2 's mac address. Will r1 note the " 56FF: FE78" in interface field and conclude this is the mac address for h2 and therefore does not need to send arp request to h2?
2) If i have to use the option of eui-64 to configure ipv6 address on interface, ipv6 sets the 7 bit to 1 to get the modified eui-64 format. My question is why? why can we not use the mac address whose 7 bit is 0?
I'm no IPv6 expert but I was thinking there is no arp. My understanding is IPv6 uses Neighbor Discovery and Multicast to get L2 info. The L2 info is part of the IPv6 address / Well the last 64 bits of the address are related to the 48 bit mac address right?
Wasn't one of the big goals of IPv6 to not have so much broadcast traffic?
Is it possible that you are pinging your own IPv6 address?
For me, the command works fine:
Switch#show ipv6 neighbors IPv6 Address Age Link-layer Addr State Interface FE80::8965:A9E6:1759:BB4F 23 36b2.ef59.5a6b STALE Vl539 FE80::20C:29FF:FE78:D92A 23 000c.2978.d92a STALE Vl638 FE80::214:5EFF:FEE0:59A2 23 0014.5ee0.59a2 STALE Vl338 3001:4118:300:122:CC7:20FF:FE5D:5F74 23 0ec7.205d.5f74 STALE Vl239 3001:4118:300:100::32 2 001a.6de9.3c9a STALE Vl238 FE80::216:76FF:FE94:A9CE 23 0016.7694.a9ce STALE Vl156
Hi everyone, I would like to thank you in advance for any help you can provide a newcomer like myself!
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