Need help with CatOS to IOS conversion

[bornno1984]

Hi folks,

Need help with conversion for QOS on CatOS 6509 to 6509-E IOS as below.

set qos wred 1p2q2t tx queue 1 40:80 70:100
set qos wred 1p2q2t tx queue 2 40:80 70:100

Am wondering if this is the default QOS on 6509 switch. If so, does it mean that there is no equivalent IOS command that is needed to be applied on IOS. I've tried using the translator but it states that there is no equivalent command during conversion. Thanks in advance

[jonathanaxford]

Hi,

As a guess, I would say this would relate to the wrr-queue random-detect min-threshold and wrr-queue random-detect max-threshold IOS commands that would be applied on a Cat6500 running IOS.

I am not entirely sure of the conversion between the two, but the Enterprise QoS SRND document from Cisco does go into the details:

http://www.cisco.com/en/US/docs/solutions/Enterprise/WAN_and_MAN/QoS_SRND/Enterprise_QoS_SRND.pdf

Check out the Catalyst 6500 Queuing and Dropping sections for more info.

Hope this helps,

Jonathan

[sfaizul]

Hi ,

Please see conversion for QOS on CatOS 6509 to 6509-E IOS as below.

set qos txq-ratio 1p2q2t 40 30 30

----------->  wrr-queue queue-limit 40 30 30



set qos wrr 1p2q2t 30 70

----------->  wrr-queue bandwidth 3 7



set qos wred 1p2q2t tx queue 1 40:80 80:100

--------->  wrr-queue random-detect min threshold 1p2q2t 80 80

            wrr-queue random-detect max threshold 1p2q2t 10 100



set qos map 1p2q2t tx 1 1 cos 1

-------->  wrr-queue cos-map 111



set qos map 1p2q2t tx 1 2 cos 0

! Assigns Best Effort to Q1 WRED Threshold 2

set qos map 1p2q2t tx 2 1 cos 2,3,4

! Assigns CoS 2,3,4 to Q2 WRED Threshold 1

set qos map 1p2q2t tx 2 2 cos 6,7





-------> wrr-queue cos-map 1 2 0

         Wrr-queue cos-map 2 1 2 3 4

         Wrr-queue cos-map 2 2 6 7





set port qos mod/port trust trust-dscp

------->  mls qos trust dscp



set qos acl ip layer2-qos trust-cos ip any any

set qos acl ip layer3-qos trust-dscp ip any any

----- The above command would the same here.

Regards

Syed.

[bornno1984]

many thanks for those for replied and viewed! i believe i got my answer.