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Block address and 1024 subnets.

question 1. In a block address, we know the IP address of one host is 182.44.82.16/26. What are the first address (network address) and the last address (limited broadcast address) in this block?

question 2. An organization is granted the block 130.56.0.0/16. The administrator wants to create 1024 subnets.

a. Find the subnet mask.

b. Find the number of addresses in each subnet.

c. Find the first and last addresses in subnet 1.

d. Find the first and last addresses in subnet 1024.

1 ACCEPTED SOLUTION

Accepted Solutions
Cisco Employee

Re: Block address and 1024 subnets.

Hi Eric,

Answer 1)

182.44.82.0 is the subnet address

182.44.82.63 is the broadcast address

Answer 2)

a) 255.255.255.192 will be the subnet mask

b) 62 valid addresses can exist in each subnet

c) First address in subnet 1 will be 130.56.0.1 and last address is sibnet 1 will be 130.56.0.62

d) First address is 1024 subnet will be 130.56.255.193 and last address in 1024 subnet will be 130.56.255.254

HTH

Ankur

*Pls rate helpfull post

2 REPLIES
Cisco Employee

Re: Block address and 1024 subnets.

Hi Eric,

Answer 1)

182.44.82.0 is the subnet address

182.44.82.63 is the broadcast address

Answer 2)

a) 255.255.255.192 will be the subnet mask

b) 62 valid addresses can exist in each subnet

c) First address in subnet 1 will be 130.56.0.1 and last address is sibnet 1 will be 130.56.0.62

d) First address is 1024 subnet will be 130.56.255.193 and last address in 1024 subnet will be 130.56.255.254

HTH

Ankur

*Pls rate helpfull post

New Member

Re: Block address and 1024 subnets.

Thanks so much!

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