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Determining "receive" side of optic SFP

Hi.

I have an implementation coming up of dark fibre which requires me to run ZX SFP's (cable distance more than 10 k's), but I need to put an attenuator into the receiving side of the SFP at each end.

How do I figure out which one is the receiver?

With the 1350nm SFP, there's no "light" to see the output and figure which is the transmitter like there is on 850nm SFP's - so how do I do it for the longer wavelength ones?

I've only been able to find a disgrametic representation of a CWDM SFP which indicates a specific side - is it safe to assume a standard, non WDM SFP is the same?

Or do I plug it in with the attenuator in one side, check the power input, then plug it in the other side and see if it makes a diference?

Thanks.

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Hall of Fame Super Gold

Determining "receive" side of optic SFP

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Hall of Fame Super Gold

Determining "receive" side of optic SFP

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Determining "receive" side of optic SFP

leolaohoo wrote:

Look at Figure 1.

Cisco SFP and SFP+ Transceiver Module Installation Notes

Yet again, your awesomness is legendary, Leo.

Try as I might, I couldn't find that document. Now I have it bookmarked.

Thanks mate!

Hall of Fame Super Gold

Determining "receive" side of optic SFP

No problem Darren.  Glad to be of some assistance.

Community Member

Also, it just would be

Also, it just would be possible to use a camera without IR-filters, to detect the light. Best would be a thermographic camera.

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