Greetings good people,
I am having trouble understanding third octet identification with class B addressing when dealing with /25 masking...
my question is what/how do we deal with the third octet as far as identifying it in dotted decimal...
172.16.0.0 /25 ........ is the answer as simple as saying "follow the new mask designation" for identifying the network portion?
if you could follow my line of thinking here for a second: overall, it does not matter that it is a class B nor what mask a B address has....because we're changing it to /25 right?
and with that thought, there are now three octets (plus one bit of the fourth) which designate the network portion of the dotted decimal address....
255.255.255.128............... leaving the host portion identifying 1-126 ..
I ask because I had confusion on what to do with the third octet.... but!! if I did the ANDing process between the /25 and 172.16.0.0 it would have been clear?
as mud.
thanks for any input...
