Link A and B or the LAN1 interfaces don't have the same bandwidth do they? The best route (lowest metric) to a destination is called the feasible distance (FD). Feasibility condition (FC) is met when the neighbor's FD, also known as reported distance (ie the total metric along a path to a destination network as advertised by an upstream neighbor), to a destination is lower than the router's current FD to the same destination. So for a route to be in the eigrp top table, the advertised distance (AD) must be less than the FD for that route.
A feasible successor is a path whose reported distance is less than the feasible distance.
Do a sh ip eigrp top x.x.x.x (where x.x.x.x is the lan 2 network) and show ip eigrp topology all-links. On routerA the AD of lan2 from linkb/routerb must be larger than the FD.
So 10.10.1.0/24 from routera is less (1764352) than the FD of routerb, but the AD is more than the FD from routerb to routera. Metric is composed outbound on an interface, and the AD from routerc is equal (both routera and routerb see the metric as 28160). For both routera and routerb to get to lan2, they must count the metric for leaving the s2/0 interface, and leaving the routerc lan2 interface. Routerc is advertising an equal metric so it leaves the serial interfaces on routera and routerb to be different. The AD on both routers from routerc is equal, the bandwidth is equal on the serial links but the FD is different so what is left - delay. Why does s2/0 on routerb have a delay of 2010 and routera doesn't? Remove that delay or add the same on routera and see what you get.
Hi everyone, I would like to thank you in advance for any help you can provide a newcomer like myself!
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