For these Tc and Bc values CIR=Bc/Tc=512 Kbps. Your packet of 12000 bits will be transmitted in less than 3 Tc intervals (12000/Bc=2.34). Considering CIR=512K and the rate you want to transmit (12000 bbps) I think there'll be no problem. Check this:
thanks for your mail. After reading your article on CCO I still have a problem of understanding.
The book "IP QoS" from Cisco Press says the following about traffic shaping on page 54:
"The maximum size of the token bucket is set to be the sum of conformed burst size, Bc and the extended burst size, Be. Tokens equivalent to Bc are added to the bucket every measuring interval T, where T = Bc/CIR. CIR is the allowed mean rate of traffic flow. If the bucket becomes full, any added tokens overflow. When a packet arrives, the token bucket is checked to see if enough tokens are available to send the packet. If enough tokens are available, the packet is marked compliant, and the tokens equivalent to the packet size are removed from the bucket. If enough tokens are not available, the packet is marked non-compliant and is queued for later transmission."
This means that a router can never transmit a packet larger than the bucket size.
But in reality, a router transmits a packet larger than the bucket size. It seems that for packets larger than the packet size, it can borrow bits from future intervals.
But I haven't found any document yet, which clearly describes this case.
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