06-26-2002 09:33 AM - edited 03-01-2019 10:48 PM
I have three switches:
Switch A, 5509
Switch B, 5505
Switch C, 3548
Switch A is connected to switch B and C
Switch B is connected to switch A and C
Switch C is connected to switch A and B
None of them is the root switch.
The state of spanning tree is this:
A(forwarding)-B(Blocked)
A(forwarding)-C(forwarding)
C(forwarding)-B(forwarding)
I would like to know if the state of A is correct. Thanks.
06-26-2002 09:33 AM
sure, there is a normal state. Some port must be blocked to avoid loops and some must be forwarding within Spanning tree.
To have a better understanding of Spanning tree, visit:
http://www.cisco.com/univercd/cc/td/doc/cisintwk/ito_doc/transbdg.htm
06-29-2002 09:02 AM
This is the normal operation to prevent network loops. There has to be a root switch according to the algorthm. Since these are all Cisco Switches, the priority is set to 32768 by default. You can adjust the priority if one of the switches is desired to be the root switch.
The switch with the highest bridge priority (the lowest numerical priority value) is elected as the root switch. If all switches are configured with the default priority (32768), the switch with the lowest MAC address in the Layer 2 network becomes the root switch.
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