Anyone knows if it's posible establish a call between two C20 Codec only dialing the ip address of each endpoint, without register the endpoints to VCS.
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Thanks for your prompt response!
Is there any specific configuration which must be done (as in H.323 direct mode) or nothing special? Unfortunately my customers do not have any VCS-C or Expressway and they have only 2 SX20 and one C20.
just set SIP mode to ON and you should be able to dial by IP address.
example: xcommand dial: sip:xxx.xxx.xxx.xxx
But I would think you would better use H323 if you do not have any VCS, since for SIP call, we only test when SIP proxy is involved.
Just want to make sure ip dialling via SIP is possible and works. Because IP dialling works only when H323 is ON though is SIP is already ON in one of my case. In this case i have VCS-C and VCS-E involved. I want to make sure IP dailling can work with SIP .
If you have VCSe, VCSc and your endpoint are SIP registered to these devices, you should dial by the SIP URI.
Yes, what if the endpoint is outside the enterprise network not registered to vcs-e. for eg i am trying to ip dial to a endpoint in internet .i think only h323 will work in this case ?
You can use SIP as well. If one of the endpoints does not support SIP or H.323 you can use the interopability option on VCS.
I be done that myself. Calling an E20 from a C20 just using up addresses. I didn't configure anything on sip profile or h323.
However when I see the call statistics it says that h323 has been use as the default protocol.
I have a question tho, I have an SX20 registered to a VCS with SIP.
I've add transform sets to allow calls from other sip devices and h323 devices and add the vcs domain.
However, when I try calling to the e20 or c20 the call doesn't go through and when I check the call history on the vcs it shows an error of sip<->blank and 404 error.
How can I fix this?
What transform can I add for the IPs of the e20 and c20 be added the @vcsdomain so that it can call my sx20.
Is this possible?
As the thread you have replied to is an older one, has been marked as answered, and is yours is not directly related to the original question, it'd be best if you opened a new discussion for your problem.
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