Have a question on the EIGRP traffic distribution count. Is there a possibility to perform the traffic distribution in 5:2 ? Below is the calculation to perform a 5:1 ratio distribution (Diagram is attached for the setup).
Note : Using only delay to perform the composite metric calculation
Path via R2 from R1 to reach Loopback on R4
Metric = 256*[sum of delay/10]
Path via R3 from R1 to reach Loopback on R4
So. Path via R2 would be successor & path via R3
As Feasible successor.
Variance = FD of FS/FD of Successor
So, 642560/133120 = 4.82
Variance = 5 (whole number)
Lowest metric (FD of the successor)* 5 = 256 * [delay/10]
So, looking at my metric figures
133120 x 5 = 256 * [delay/10]
665600/256 = delay/10
26000 = delay
Now, to determine the local interface delay (LD), we need to subtract the relative distance delay in order to get the LD.
R3 - R4 has a cumulative delay of 5100.
So, 26000 - 5100 = 20900
Now, by setting the delay value of 2090 on the R1 interface connecting to R3, i would achieve 5:1. What can be done to get 5:2 ?
This is actually a pretty cool feature, i didn't even know it existed until I was looking for a solution to advertise a subnet (prefix in BGP talk), only if a certain condition existed. This is exactly what conditional advertisements does
j ai une question j ai achete un routeur cisco 887VA-k9 , je le configuré avec la configuration ci- dessous
si je le lier avec mon pc portable sur l un de ses ports directement ça marche toute est bien ( la connexion internet + m...
Attached policy provides CLI access to the Cisco 4G router over text messaging. Two files are in the attached .tar file:
2. PDF with instructions on how to load and use the .tcl file.