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heplz in the command # sh ip eigrp to all-links

i have a auestion in the command #sh ip eigrp to all

i enclosed a figure s0 as to explain my question

==========================

now when i go to wan1 and type sh ip eigrp to all

===================================================

Codes: P - Passive, A - Active, U - Update, Q - Query, R - Reply,

r - reply Status, s - sia Status

P 10.11.1.0/24, 1 successors, FD is 2172416

via 10.1.1.2 (2172416/28160), Serial0/0/0.1

! lines omitted for brevity; no other lines of output pertain to 10.11.1.0/24.

WAN1#show ip eigrp topology all-links

IP-EIGRP Topology Table for AS(1)/ID(10.9.1.1)

Codes: P - Passive, A - Active, U - Update, Q - Query, R - Reply,

r - reply Status, s - sia Status

P 10.11.1.0/24, 1 successors, FD is 2172416, serno 45

via 10.1.1.2 (2172416/28160), Serial0/0/0.1

via 10.9.1.2 (2174976/2172416), FastEthernet0/0

! lines omitted for brevity; no other lines of output pertain to 10.11.1.0/24.

=====================================================

why there is  path to the route 10.11.1.0/24 through B2????

i read from the book

(

the path to 10..11.1.0/24 is not listed  through Router B2 (10.1.1.6) at all, because B2’s current successor route

for 10.11.1.0/24 is through WAN1. EIGRP Split Horizon rules tell B2 to not advertise

10.11.1.0/24 to WAN1.

)

what does the split horiozon do here???????"

should i disable it??

or it is a

Precaution to prevent the loops???

thanks alot

1 REPLY
Hall of Fame Super Silver

heplz in the command # sh ip eigrp to all-links

answered in other thread

let's go on there for clarity opening muliple threads does not help

Best Regards

Giuseppe

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