cancel
Showing results for 
Search instead for 
Did you mean: 
cancel
1174
Views
0
Helpful
7
Replies

Ip subnetting

dasadino2003
Level 1
Level 1

Hi all,

I am currently trying to create 3 subnets with a class A ip address (10.14.227.0 /24).Unfortunately, my knowledge for subnetting is close to non existence and i would appreciate if someone could help me with it thanks.

1 Accepted Solution

Accepted Solutions

Hi,

I think you are trying to equally subnet 10.14.227.0/24 to 3 subnets. That won't happen.

However, you can create four equal subnets out of it;

10.14.227.0/26 that is 10.14.227.1 to 10.14.227.62 (max 62 hosts)

10.14.227.64/26 that is 10.14.227.65 to 10.14.227.126 (max 62 hosts)

10.14.227.128/26 that is 10.14.227.129 to 10.14.227.190 (max 62 hosts)

10.14.227.192/26 that is 10.14.227.193 to 10.14.227.254 (max 62 hosts)

or three subnets (two equal, one bigger)

10.14.227.0/25 that is 10.14.227.1 to 10.14.227.126 (max 126 hosts)

10.14.227.128/26 that is 10.14.227.129 to 10.14.227.190 (max 62 hosts)

10.14.227.192/26 that is 10.14.227.193 to 10.14.227.254 (max 62 hosts)

/25 subnet mask is 255.255.255.128

/26 subnet mask is 255.255.255.192

Step-by-step tutorial from http://www.ralphb.net/IPSubnet/ just select "Next" to go to next page.

Subnet calculator from Boson and other utilities http://www.boson.com/FreeUtilities.html

View solution in original post

7 Replies 7

avmabe
Level 3
Level 3

I have tried the subnetting calcualtor but its seems not to help, please can u help me subnet the ip address 10.14.227.0/24 and give my the host range in each of the 3 subnets .thanks

Adedayo,

I don't know if your question was intended for learning subnetting or just looking for a solution. Assuming you are looking for a solution you can break the /24 into 3 subnets the following way. Instead, if you are trying to learn subnetting there are plenty of free tools available online or let us know.

10.14.227.0/26 - 10.14.227.1 - 10.14.227.62 are usable addresses. .63 is the broadcast address for this subnet.

10.14.227.64/26 - 10.14.227.65 - 10.14.227.126 are usable addresses .127 is the broadcast address.

10.14.227.128/25 - 10.14.227.129 - 10.14.227.254 are usable addresses. .255 is the broadcast address.

HTH

Sundar

Hi,

I think you are trying to equally subnet 10.14.227.0/24 to 3 subnets. That won't happen.

However, you can create four equal subnets out of it;

10.14.227.0/26 that is 10.14.227.1 to 10.14.227.62 (max 62 hosts)

10.14.227.64/26 that is 10.14.227.65 to 10.14.227.126 (max 62 hosts)

10.14.227.128/26 that is 10.14.227.129 to 10.14.227.190 (max 62 hosts)

10.14.227.192/26 that is 10.14.227.193 to 10.14.227.254 (max 62 hosts)

or three subnets (two equal, one bigger)

10.14.227.0/25 that is 10.14.227.1 to 10.14.227.126 (max 126 hosts)

10.14.227.128/26 that is 10.14.227.129 to 10.14.227.190 (max 62 hosts)

10.14.227.192/26 that is 10.14.227.193 to 10.14.227.254 (max 62 hosts)

/25 subnet mask is 255.255.255.128

/26 subnet mask is 255.255.255.192

Step-by-step tutorial from http://www.ralphb.net/IPSubnet/ just select "Next" to go to next page.

Subnet calculator from Boson and other utilities http://www.boson.com/FreeUtilities.html

If you use the last subnet with a broadcast address of 10.14.227.255, and a broadcast is sent, would this broadcast not get dilevered to ALL hosts on all 4 subnets of the 10.14.227.0 network? Could this not create unnecessary congestion for hosts on the first 3 subnets?

I'm also curious as to why the private 10.0.0.0 network was carved into 10.14.227.0. This leaves only 6 bits for hosts and 18 bits for subnets. Unless it is for practice with the equivalent of a class C network, what is the reason?

"If you use the last subnet with a broadcast address of 10.14.227.255, and a broadcast is sent, would this broadcast not get dilevered to ALL hosts on all 4 subnets of the 10.14.227.0 network?"

Hopefully for security reasons you have IP directed broadcasts disabled so this won't be an issue.

albert.remo
Level 1
Level 1

Hi!

Good Day. Please see my summary about subnetting. Hope this helps!

Regards,

Albert

Getting Started

Find answers to your questions by entering keywords or phrases in the Search bar above. New here? Use these resources to familiarize yourself with the community:

Review Cisco Networking products for a $25 gift card