12-18-2007 07:34 PM - edited 03-03-2019 07:59 PM
Hello All!
I think I am having a fundamentally wrong understanding of how EIGRP treats routes that have been redistributed from a different routing protocol.
I have 2 routers connected together
R4----R5
I am redistributing OSPF into EIGRP on R4
On R4:
router eigrp 10
redistribute ospf 1 metric 1500 1 255 1 1500
network 129.186.0.0
network 180.1.0.0
no auto-summary
!
On R5 I find my redistributed routes in the EIGRP topology table, however, they show all up like this
P 10.4.4.0/24, 0 successors, FD is Inaccessible
via 129.186.54.2 (2218752/1706752), Serial0/0.45
R5#sh ip eigrp topology 10.4.4.0 255.255.255.0
IP-EIGRP (AS 10): Topology entry for 10.4.4.0/24
State is Passive, Query origin flag is 1, 0 Successor(s), FD is 4294967295
Routing Descriptor Blocks:
129.186.54.2 (Serial0/0.45), from 129.186.54.2, Send flag is 0x0
Composite metric is (2218752/1706752), Route is External
Vector metric:
Minimum bandwidth is 1500 Kbit
Total delay is 20010 microseconds
Reliability is 255/255
Load is 1/255
Minimum MTU is 1500
Hop count is 1
External data:
Originating router is 10.4.4.4
AS number of route is 1
External protocol is OSPF, external metric is 0
Administrator tag is 0 (0x00000000)
What am I doing wrong here?
Thanks
Sascha
12-18-2007 07:54 PM
I have solved it. I should have thought twice before writing.
The problem was that on R5 I also have an OSPF adjacency. The OSPF routes have a better AD, so that's why my redistribution didn't work.
12-18-2007 09:29 PM
Yes..
FD inaccessible is an indication that the particular prefix has not been installed in the routing table by EIGRP
Narayan
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